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Choose the correct answers for each of the following questions.

1.     Which one of the following group is comprised of the elements           

(a)        Mercury, Water, Ammonia     

(b)        iodine, Tin, Iron        

(c)        Copper, Aluminium, Methane

(d)        Coal, Smoke, Fog

2.     Which one of the following can be broken down into simpler substances.

(a)        Ammonia                   

(b)        Oxygen                                               

(c)        Sulphur

(d)        Iron filling

3.     The gram molecular mass of HNO3 is                                         

(a)        60                   

(b)        100                                         

(c)        63                   

(d)        98

4.     Which of these molecules is not a compound:                                       

(a)        N2O                 

(b)        N2                                           

(c)        NO                  

(d)        NO2

5.     Which of the following is equal to two moles of water (H2O)

(a)        1.084 x 1025  molecules         

(b)        6.022 x 1023 molecules

(c)        1.204 x 1024 molecules          

(d)        1.806 x 1024 molecules

6.     A compound contains

(a)        Different kinds of atoms mixed together                  

(b)        the same kind of atoms mixed together

(c)        Different kinds of atoms chemically combined together      

(d)        The same kind of atoms chemically combined together

7.     Which one of the following is an example of triatomic molecule

(a)        CO2                 

(b)        O2                               

(c)        CH4                             

(d)        NH3

8.     Hydrogen gas is

(a)        A monoatomic gas     

(b)        A mixture of hydrogen atoms

(c)        A diatomic gas with each molecule made up of two atoms             

(d)        A diatomic atom made up of two molecules

9.     Which of the following compounds has both empirical and molecular formula identical         

(a)        Benzene (C6H6)                                              

(b)        Hydrogen-per-Oxide (H2O2)

(c)        Water (H2O)              

(d)        Glucose (C6H12O6)

10.            Which one of the following is a homogeneous mixture                    

(a)        Smoke             

(b)        Air                                          

(c)        Fog                             

(d)        Smog              

Exercise Short Questions

How many elements are present in each of the following? 

HF and HCl, Co and CO, Si and SiO2, POCl2 and POCl3

Solution          

(a) In HF there are two elements while HCl also consists of two elements.  

(b) Co is one element while in CO there are two elements.

(c) Si is one element while in SiO2 there are two elements.

(d) In POCl2 there are three elements while in POCl3 there are also three elements.

 

Cm is the chemical symbol for curium, named after the famous scientist Madam Curie. Why wasn’t the symbol C, Cu or Cr used instead? 

The symbols of elements should be unique so that they can be easily identified. For this reason, C, Cu, and Cr are not the symbols of Curium because C is the symbol of Carbon, Cu is the symbol of Copper while Cr is the symbol of Chromium.

What is the atomic number of an element? How does it differ from the mass number 

Note: The answer to this question is already attempted in the ”Short question’s answers” section of Class 9 Chemistry Notes.

Differences between atomic number and mass number

Atomic number

Mass Number

The number of protons present in the nucleus of an atom is called the atomic number.

The sum of the number of protons and neutrons present in the nucleus of an atom is called the mass number.  

The atomic number is represented by the capital letter Z.

The atomic number is represented by the capital letter A.

It is written at the subscript position of the symbol of the element i.e. AXZ.

It is written at the superscript position of the symbol of element i.e. AXZ

The modern periodic table is arranged on the basis of the increasing order of atomic numbers.

The old periodic table was arranged on the basis of the increasing order of atomic masses.

It has no unit.

It has the unit “amu”.

Examples:

Na=11, C=6, O=8, N=7, Cl=17 etc.

Examples:

Na=23 amu, C=12 amu,

O=16 amu, N=15 amu, Cl=35.5 amu etc.

 

Students often mix up the following elements. Give the names for each element.

Mg and Mn, K and P, Na and S, Cu and Co.

(a)

Mg is the symbol of Magnesium

and

Mn is the symbol of Manganese.

(b)

K is the symbol of Potassium

and

P is the symbol of Phosphorus

(c)

Na is the symbol of Sodium

and

S is the symbol of Sulphur

(d)

Cu is the symbol of copper

and

Co is the symbol of Cobalt.

 

(a) Classify the following molecules as mono-atomic, diatomic, triatomic, and polyatomic molecules.

Monoatomic molecules

Diatomic molecules

Triatomic molecules

Polyatomic molecules

He, Ar

N2, HCl,

H2O, CO2

S8, H2SO4,

C6H12 O6

(b) Classify the following as cation, anion, molecular ion, free radicals, and molecules.

Cation

Anion

Molecular Ion

Free radical

Molecules

Mg+2, Na+

O-2, Cl-,

CH+, CO+, CO3-2, C2H5O-1

CH3

CO3, O2, H2O, Cl2.

Solutions to Numericals Involving Chemical Calculations

Calculate the number of moles of Butane C4H10 in 151 g of Butane.  (at.masses of C=12 amu and H=1 amu).

Given data

No of moles of C4H10 = ?                  Mass in grams = 151 g

Solution

The formula of      No of moles =  (Mass in grams) / (Molar mass)…………..(A)

But    Molar mass of C4H10   = 4 (at.mass of C) + 10 (at.mass of H)                                                          = 4 (12 g) + 10 (1 g)                                                                                                   

= 48 g + 10 g                                                                                                              

= 58 g                          

Now by putting the values in eq (A), we have 

No of moles of C4H10 =       151g / 58 g 

= 2.63 moles   Answer.

What is the mass of 5 moles of ice? (At.masses: H = 1 amu, 

O = 16 amu)

Given Data                                                                                                                                                  

Mass in gram of Ice = ?                                                                                                         

No of moles of Ice = 5 moles                                     

Solution                                                                                                       

As        No of moles=  (Mass in grams)/(Molar mass)________ eq (A)

and      Molar mass of H2O = 2 (at.mass of H) + 1(at.mass of O) 

= 2 (1 g) + 1 (16 g)                                                                                                     

= 2g + 16g                                                                                                                              

=18g                                       

Now by putting the values in eq (A), we have                                                                                                           

5 =   (Mass in gram)/18g   

By cross multiplication, we have       

Mass in gram of Ice = 5 x 18                                                                                                             

= 90g   Answer.

Viii:     Calculate the number of molecules in 6.50 mol of CH4

Given:              No of moles= 6.50 mol            No of molecules=?

Solution:

As        No of moles= (No of atoms/molecules) / (Avogadro’s Number (NA)

Or        o of molecules=No of moles x NA………(i)   

Putting the values in eq (i), we have

No of molecules = 6.50 mol x  6.023 x 1023

No of molecules = 39.149 x 1023  molecules

No of molecules = 3.914 x 1024  molecules    Ans

Ix:        Calculate the average atomic mass of Lithium from the following data.


Isotope

Natural abundance (%)

Relative atomic mass (amu)

6Li

7.5

6.0151

7Li

92.5

7.0160

Average atomic mass of Lithium (Li) = ?

Data 

1St Isotope of Li= 6.0151                  %abundance of Li-6= 7.5 %            

2nd Isotope of Li=7.0160                  %abundance of Li-7= 92.5 %

Required          Average atomic mass of Lithium?

Solution

The formula for finding the average atomic mass of an element is given as

=  (1st isotope x its %age) + (2nd isotope x its %age) + ….…) / 100       

Putting the values for Li in the above equation                                                               

Average atomic mass of Li =  (1st Isotope × its% )  +  (2nd Isotope × its%) / 100                                    

= (6.0151 × 7.5) + (7.0160×92.5) / 100                                   

= (45.113+648.98) / 100                                                                                                                      

= 694.0 /  100                                                                                                                            

= 6.94 amu                  Ans

X:         Calculate the mass of 6.68 x 1023  molecules of PCl3.

Given:              No of molecules of PCl3 = 6.68 x 1023  molecules of PCl3

                        Mass in gram=?

Solution:

As we know that                                                                                                                                

No of moles =  (No of atoms or molecules) / (Avogadro's No (NA)  _______ (A)

Putting the values in eq (A), we have

No of moles = 6.68 x 1023 / 6.023 x 1023  molecules of PCl3

No of moles = 1.109

No of moles =  Mass in grams / Molar mass

Or        Mass in gram = No of moles x Molar mass__________ (B)             

Molar mass of PCl3  =  1 (31) + 3 (35.5)                                                                                               

=  31 g + 106.5 g                                                                                                          

= 137.5 g                                            

Now putting the values in eq (B)                                                                               

Mass in gram = 1.109  x 137.5                                                                      

No of moles = 152.48 moles                                       

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